KU 1st in final AP Poll, 220th in a row

KU finished the season No. 1 in the AP and the coaches poll as well. That is 220 consecutive AP polls, 1 short of the record by UCLA.
If KU is in the preseason AP Poll next season, they will tie the record for longest consecutive streak. KU received 63 of 65 first place votes and 2nd in the other two votes. In the Coaches poll some coach voted KU 4th, 2 voted 2nd and 29 voted 1st. Who the heck had KU 4th? Scott Drew is one of the 25 coaches voting. Here are the coaches voting.

Randy Bennett, Saint Mary's
Jim Boeheim, Syracuse
Glenn Braica, St. Francis (N.Y.)
Tim Cluess, Iona
Jon Coffman, Purdue Fort Wayne
Tom Crean, Georgia
Scott Drew, Baylor
Matt Driscoll, North Florida
Steve Forbes, East Tennessee State
Mark Fox, California
John Gallagher, Hartford
Steve Hawkins, Western Michigan
Ron Hunter, Tulane
George Ivory, Arkansas-Pine Bluff
Ben Jacobson, Northern Iowa
Chris Jans, New Mexico State
James Jones, Yale
Greg Kampe, Oakland
Danny Kaspar, Texas State
Shantay Legans, Eastern Washington
Grant McCasland, North Texas
Mike McConathy, Northwestern State
Robert McCullum, Florida A&M
Greg McDermott, Creighton
Matt McMahon, Murray State
Dan Monson, Long Beach State
Chris Mooney, Richmond
Matt Painter, Purdue
Dave Pilipovich, Air Force
Brett Reed, Lehigh
Tubby Smith, High Point
Zach Spiker, Drexel.

Corpus, do you know how how they select the coaches to vote.

And just to clarify, do you mean 32 coaches? (That's the number of coaches I counted on your list.)

Ken Pomeroy’s Final College Basketball Top 25 Rankings

KenPom, too

< thespun.com/college-hoops/ken-pomeroys-f...Ec3Lwt9niBvuyMvOjL8M >

No idea where the 25 came from. A demon in my fingers I suppose. Yes of course there are 32 coaches voting in the poll. As for how they are selected, I believe there are 3 criteria.

1. They must be a member of the coaches association (which pretty much all of them are)
2. They must submit a willingness to be part of the poll
3. 32 will be randomly drawn , one from each conference, from those who fulfill one and two

I'm pretty sure that is how it works.